F(x-2)=5x^2-3x+4

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Solution for F(x-2)=5x^2-3x+4 equation: 



(F-2)=5F^2-3F+4

We move all terms to the left:

(F-2)-(5F^2-3F+4)=0

We get rid of parentheses

-5F^2+F+3F-2-4=0

We add all the numbers together, and all the variables

-5F^2+4F-6=0

a = -5; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-5)·(-6)
Δ = -104
Delta is less than zero, so there is no solution for the equation

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